Asked by London
How would you solve for:
(the square root of 7-the square root of 3)^2
^=the power of
[sqrt(7) - sqrt(3)]^2 =
7 + 3 - 2sqrt(21) = 10 - 2sqrt(21)
(the square root of 7-the square root of 3)^2
^=the power of
[sqrt(7) - sqrt(3)]^2 =
7 + 3 - 2sqrt(21) = 10 - 2sqrt(21)
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