To factor out the GCF (Greatest Common Factor) from the expression \(18x^3y^4 + 12x^5y^2\), we first determine the GCF of the coefficients and the variables separately.
- Coefficients: The coefficients are 18 and 12. The GCF of 18 and 12 is 6.
- Variable Terms:
- For \(x\): The minimum exponent in \(x^3\) and \(x^5\) is \(x^3\).
- For \(y\): The minimum exponent in \(y^4\) and \(y^2\) is \(y^2\).
Now we can combine these to get the GCF for the entire expression: \[ \text{GCF} = 6x^3y^2 \]
Next, we divide each term in the original expression by the GCF:
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For \(18x^3y^4\): \[ \frac{18x^3y^4}{6x^3y^2} = 3y^2 \]
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For \(12x^5y^2\): \[ \frac{12x^5y^2}{6x^3y^2} = 2x^2 \]
Now we can rewrite the expression by factoring out the GCF: \[ 18x^3y^4 + 12x^5y^2 = 6x^3y^2(3y^2 + 2x^2) \]
Thus, the rewritten expression is: \[ \boxed{6x^3y^2(3y^2 + 2x^2)} \]