How would you prepare 3.5 L of a 0.9M solution of KCl?

Question

A. Add 23 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
C. Add 287 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
D. Add 567 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.

Answer 1

mass=Molarity*molemas*volume
= .9*74.5*3.5= you do it.

Then add water to the 3.5Liter mark, stir, and label.