L x M = moles
You have L and M, solve for moles.
Then
moles = grams/molar mass
You have moles and molar mass, solve for grams.
This is used sometimes as a trick question; the procedure is to weigh out the mass (grams) needed, place in a 1 L volumetric flask, and make to a final volume of 1 L and NOT add 1 L of water
how would you prepare 1L of a .5M solution of each of the following?
Sodium carbonate from the pure solid
1 answer
1 answer