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How would you find the number of grams of NH3 that is produced from 35 L of N2 at 200 atm pressure and a temperature of 450 degrees C?

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3H2 + N2 <--> NH3 If 35 L of N2 then 70L of NH3 PV = nRT so n = PV/RT
200 x 70 / 8.314 x 723

That get's n = number of mols at the conditions listed, then mols = grams/molar mass and solve for grams.

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