Asked by Mira
How would you find the following. A step by step process would greatly be appreciated.
1) Convert the polar equation to a rectangular equation.
r^2 = 8sin2θ
1) Convert the polar equation to a rectangular equation.
r^2 = 8sin2θ
Answers
Answered by
MathMate
hints:
use the relations:
x=rsinθ
y=rcosθ
which means the left-hand side
=x²+y²=r²
Also
8sin2θ = 16 sinθcosθ
=16(y/r)(x/r)
=16xy/r²
Equating both sides,
x²+y² = 16xy/r²
or
(x²+y²)² = 16xy
=2xy/(x²+y²)
use the relations:
x=rsinθ
y=rcosθ
which means the left-hand side
=x²+y²=r²
Also
8sin2θ = 16 sinθcosθ
=16(y/r)(x/r)
=16xy/r²
Equating both sides,
x²+y² = 16xy/r²
or
(x²+y²)² = 16xy
=2xy/(x²+y²)
Answered by
Mira
Thank you so much. I was stuck on the right hand side with the 8sin2θ. Not sure what to do with the 8 and 2.
This has cleared it up very well.
This has cleared it up very well.
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