How would you calculate the percent yield for a reaction that began with 10 moles of acetone and 16 moles of benzaldehyde which yielded 6 moles of dibenzalacetone as the product? The molecular weights are as follows (acetone = 58.08 g/mole), (benzaldehyde = 106.2 g/mole), (dibenzalacetone = 234.3 g/mole. Thanks.
1. Write the balanced equation.
2. Calculate theoretical yield; i.e., how much product (in mols) SHOULD you get, using stoichiometry.
3. Then
%yield = [6 mols/theoretical mols]x100 =??
1 answer