How would the calculation percent of oxalate of the unknown affected when weighting out the unknown solid the actual mass is .758 grams however the mass is mistakenly recorded as .785 grams

Answer 1

mols oxalate = grams/molar mass. Too high grams means too high mols.

Convert to mols KMnO4 means too high mols KMnO4.

M KMnO4 = mols/L. Too many mols means M too high.

Answer 2

Ok thanks. I understand