so, you couldn't fix it and finish it off? The method was right in front of you ...
r = 8sinθ - 2cosθ
r^2 = 8r sinθ - 2r cosθ
x^2+y^2 = 8y-2x
That's ok as an equation, but I suspect you want a more standard form, so keep working it, completing the squares:
x^2+2x + y^2-8y = 0
x^2+2x+1 + y^2-8y+16 = 1+16
(x+1)^2 + (y-4)^2 = 17
How would I rewrite this in rectangular form? //
r = 8 sin theta - 2 cos theta?
I apologize, there was an error before.
1 answer
1 answer