(z-y)/z = 1 - (y/z) = x/y
y/z = 1 - (x/y)= (y-x)/y
z/y = y/(y-x)
z = y^2/(y-x)
How would I make z the subject of the formulae:
x=y(z-y)/z
1 answer
x=y(z-y)/z
1 answer
1 answer
2 answers
1 answer
1 answer