How would I make 500 ml's of a .35M NaCI solution. MW= 58.44

Question

( I know how to do the first part)

How many micromoles of NaCI would be present in that solution?

What would be the percentage of NaCI in that solution?

Answer 1

How many mols do you want? That's M x L = 0.35 x 0.500 = 0.175 mols.
Then grams = mols x molar mass = 0.175 x 58.44 = approx 10.3 grams NaCl but you need to get a more accurate number.

b. There are 0.175 mol and that x 1E6 to give micromoles.

c. % what? w/w; w/v; ? I will assume you want % mass/volume
%NaCl = grams NaCl/100 g solution
You have approx 10.3g in 500 mL or
(10.3g/500)*100 = % w/v

Answer 2

thanks that is exactly how the teacher gave us the questions