if you are dealing with real numbers only, then (3-x-4)>=0
If you are dealing with principal roots only, then sqrt of anything is >0.
However, in the real world of math, one can take a root of a complex number, and those roots can be + or -.
how would i get the domain and range of f(x)= sq.root of 3-x-4? pls. explain.
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