It might look better this way...
lim x-->3 (x^3 -27)/(x^2 -9)
How would I find the limit of (if it exists):
lim x-->3 (x^3-27)
--------
(x^2-9)
2 answers
it factors
lim x-->3 (x^3 -27)/(x^2 -9) ax x--->3
= lim [(x-3)(x^2 + 3x + 9)]/[(x+3)(x-3)]
= lim (x^2 + 3x + 9)/(x+3)
= (9+9+9)/(3+3)
= 9/2
lim x-->3 (x^3 -27)/(x^2 -9) ax x--->3
= lim [(x-3)(x^2 + 3x + 9)]/[(x+3)(x-3)]
= lim (x^2 + 3x + 9)/(x+3)
= (9+9+9)/(3+3)
= 9/2