How would I find the derivative of (8x^3)/sqrt(3x-2)?

Answer 1

I would write it as

y = (8x^3)(3x-2)^(-1/2) and use the product rule

dy/dx = (8x^3)(-1/2)(3x-2)^(-3/2) (3) + 24x^2 (3x-2)^(1/2)

I will let you clean it up a bit