(1) Multiply them out.
(2) Combine terms with the same exponent of x
(3) Try to factor what is left
The last step will probably be the hardest, but you need to get there first.
How would I factor this?
(x-3)^3+ (3x-2)^3
Can someone explain this to me step by step? thanks
2 answers
dont you have a formula for the factors of two cubes?
a^3+b^3= (a+b)(a^2-ab+b^2)
Here, a is x-3 and b is 3x-2.
a^3+b^3= (a+b)(a^2-ab+b^2)
Here, a is x-3 and b is 3x-2.