how would I draw this compound?

Question

2-bromo-6-chloro-4,4-dimethylheptane

I've tried it again and again but I can't seem to get the Cl on the 6th carbon while still having a 6 carbon chain of heptane

I drew it
so that

it was
CH3 CBr CH2 CCH3CH3 CH2 Cl

I just can't figure it out..can someone help me?

Thanks

Answer 1

heptane is a seven chain...

Answer 2

I know but the problem is when I have to fit the Cl on the 6th carbon...but I can't seem to do that without putting in too much carbons.

Answer 3

Take your structure in the first post and simply add CH3 at the end (substitute CH3 for one of the Hs on the CH2Cl. I THINK your problem is you are counting one of the dimethyl groups as one of the carbons in the chain for heptane.

CH3
|
CHBr
|
CH2
|
C(CH3)2
|
CH2
|
CHCl
|
CH3
Check out my try and see if it has any flaws.