There are 3 common ways to solve quadratic equations
1. by factoring --- only works for some
2. completing the square --- works really well if it starts with 1x^2 and the middle term is even
3. the quadratic formula --- always workd
for x^2 + 2x - 7=0 I would use "completing the square"
x^2 + 2x + 1 = 7+1
(x + 1)^2 = 8
x+1 = √8 = 2√2
x = -1 ± 2√2
for 6x2 - 2x - 1= 0 I would use the formula , which I assume you know
x = (2 ± √28)/12
= (2 ± 2√7)/12
= (1 ± √7)/6
how would i do these problems:
6. xsquared + 2x -7 =0
7. 6xsquared - 2x -1 = 0
3 answers
thanks so much!
what about
4xsquared + 4x - 3= 0
what about
4xsquared + 4x - 3= 0
done here
http://www.jiskha.com/display.cgi?id=1365552528
http://www.jiskha.com/display.cgi?id=1365552528