How would I differentiate

Question

y = 4cos(2x)cos(3x)

u = cos(2x)
u' = -2sin(2x)

v = cos(3x)
v' = -3sin(3x)

This is all I have so far

Answer 1

you have to use the product rule,
with your notation, it would be

d(uv) = uv' + vu'

= (-8sin(2x))(cos(3x)) + (4cos(2x)(-3sin(3x) )
= -8sin(2x)cos(3x) - 4sin(3x)cos(2x)