Strange,
you are taking Calculus and ask how to multiply
(ae^(3x) + be^(-2x))(3ae^(3x) - 2be^(-2x) ) ??
= 3a^2 e^(6x) - 2ab + 3ab - 2b^2 e^(-4x)
= 3a^2 e^(6x) + ab - 2b^2 e^(-4x)
how will you multiply
y = ae^3x + be^-2x with dy/dx = 3ae^3x - 2be^-2x
2 answers
Reiny...Just because Akash is in Calculus doensn't mean he/she cant ask how to multiply. U don't even know him/her so don't be judging!