Asked by Hello
How to write this in expanded
(X^2)^3
(X^2)^3
Answers
Answered by
GPT-4o mini
To expand \((X^2)^3\), you can use the power of a power property, which states that \((a^m)^n = a^{m \cdot n}\).
Applying this property:
\[
(X^2)^3 = X^{2 \cdot 3} = X^6
\]
So, the expanded form of \((X^2)^3\) is \(X^6\).
Applying this property:
\[
(X^2)^3 = X^{2 \cdot 3} = X^6
\]
So, the expanded form of \((X^2)^3\) is \(X^6\).
Answered by
GPT-4o mini
Certainly! To expand \((X^2)^3\):
1. Start with \((X^2)^3\).
2. You multiply the exponents: \(2 \times 3 = 6\).
3. So, \((X^2)^3\) becomes \(X^6\).
The final result is \(X^6\).
1. Start with \((X^2)^3\).
2. You multiply the exponents: \(2 \times 3 = 6\).
3. So, \((X^2)^3\) becomes \(X^6\).
The final result is \(X^6\).
Answered by
GPT-4o mini
Let’s clarify the steps in a simpler way without symbols that might confuse.
When we start with \((X^2)^3\):
1. **Break down \(X^2\)**: This means \(X \times X\).
2. **Now raise it to the power of \(3\)**: This means you take \(X \times X\) and repeat it 3 times, like this:
- First \(X^2\): \(X \times X\)
- Second \(X^2\): \(X \times X\)
- Third \(X^2\): \(X \times X\)
Now, it looks like this:
\[
(X \times X) \times (X \times X) \times (X \times X)
\]
3. **Count the total number of \(X\)s**: You have \(3\) groups of \(2\) \(X\)s, which gives you \(3 \times 2 = 6\) \(X\)s.
So you can rewrite it as:
\[
X \times X \times X \times X \times X \times X
\]
4. **This simplifies to**:
- \(X^6\)
Thus, the expanded form of \((X^2)^3\) without using complex symbols is just \(X\) multiplied by itself six times, or simply \(X^6\).
When we start with \((X^2)^3\):
1. **Break down \(X^2\)**: This means \(X \times X\).
2. **Now raise it to the power of \(3\)**: This means you take \(X \times X\) and repeat it 3 times, like this:
- First \(X^2\): \(X \times X\)
- Second \(X^2\): \(X \times X\)
- Third \(X^2\): \(X \times X\)
Now, it looks like this:
\[
(X \times X) \times (X \times X) \times (X \times X)
\]
3. **Count the total number of \(X\)s**: You have \(3\) groups of \(2\) \(X\)s, which gives you \(3 \times 2 = 6\) \(X\)s.
So you can rewrite it as:
\[
X \times X \times X \times X \times X \times X
\]
4. **This simplifies to**:
- \(X^6\)
Thus, the expanded form of \((X^2)^3\) without using complex symbols is just \(X\) multiplied by itself six times, or simply \(X^6\).
Answered by
GPT-4o mini
Great! I'm glad that explanation helped. If you have any more questions or need further clarification on anything else, feel free to ask!
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