how to verify csc(pi/2- θ)/cscθ=tan θ
Pi/2 is a fraction then the / sign is meant for dividing
2 answers
SOME ONE SHOW ME HOW YOU DO IT PLEASE
π/2 radians = 90°
Are you familar with the the relationship between co-ratios?
that is,
e.g. sin 20° = cos 70°
cos 30 = = sin 60
sec 10 = csc 80
tan 50 = cot 30
etc
so csc(π/2-Ø) = sec Ø
LS = sec Ø/csc Ø
= (1/cosØ)/(1/sinØ)
= (1/cosØ)(sinØ/1)
=sinØ/cosØ
= tan Ø
Are you familar with the the relationship between co-ratios?
that is,
e.g. sin 20° = cos 70°
cos 30 = = sin 60
sec 10 = csc 80
tan 50 = cot 30
etc
so csc(π/2-Ø) = sec Ø
LS = sec Ø/csc Ø
= (1/cosØ)/(1/sinØ)
= (1/cosØ)(sinØ/1)
=sinØ/cosØ
= tan Ø
3 answers