how to solve this x^2-14+49=16

Answer 1

x^2-14x+49=16
(x-7)^2 = 16
x-7 = ±4
x = 7±4 = 3,11

or, just use the quadratic formula. Not really necessary here, since the left side was conveniently a perfect square.

x^2 - 14x + 33 = 0
x = (14±√(196-132))/2
= (14±√64)/2
= 7±4