What is a "po" ??
are we solving 4(4x)^2 + 2(4x) + 5 = 0 ??
(we "solve" equations, you had no equation)
let 4x = y, so your equation becomes
4y^2 + 2y + 5 = 0
y = (-2 ± √-76)/8
= (-2 ± 2√19 i)/8 = (-1 ± √19 i)/4
4x = (-1 ± √19 i)/4
x = (-1 ± √19 i)/16
how to solve this po?
4(4x)^2 + 2(4x) + 5
I hope you can answer this for me. and thank you very much. :)
1 answer