(x+1)2=9
2x + 2 = 9
2x = 7
x = 3.5
how to solve the following equations giving your answer correct to 2 decimal places where necessary
(a) (x+1)2=9
2 answers
Since a constant multiplier is not usually written behind a binomial, I suspect you meant:
(x+1)^2 = 9
then x+1 = ±√9 = ±3
x+1 = 3 ----> x = 2
or
x+1 = -3 ---> x = -4
(x+1)^2 = 9
then x+1 = ±√9 = ±3
x+1 = 3 ----> x = 2
or
x+1 = -3 ---> x = -4
1 answer