how to solve log basex 8=-1/2

Question

pls help

Answer 1

http://www.jiskha.com/display.cgi?id=1342557692

Answer 2

log basex8= -1/2

so rearrange it, therefore

x^-1/2 = 8

1/root(x) = 8

8root(x)=1

root(x)=1/8

x = (1/8)^2

so ur answer for x is x= 1/64