How to solve for the surface area of a cylinder with a base of 10 and a diameter of 6

1 answer

Surface area of a cylinder = 2πr2 + 2πrh

r = radius = 3 (diameter of 6 divided by 2)

h = height = 10

Surface area of a cylinder = 2π(3)2 + 2π(3)(10)

Surface area of a cylinder = 18π + 60π

Surface area of a cylinder = 78π