okay, one more time. Next time show your work ...
3x^2 - 7x = -4
3(x^2 - 7/3 x) = -4
3(x^2 - 7/3 x + (7/6)^2) = -4 + 3(7/6)^2
3(x - 7/6)^2 = 1/12
(x - 7/6)^2 = 1/36
x - 7/6 = ±1/6
x = (7±1)/6
x = 4/3 or 1
How to solve by using the Quadratic Formula
6x2 - 7x = - 4
1 answer