If you insist on elimination.... (substitution would be easy)
first arrange them in proper form:
2e - 5d = 14
5e - d = 12
multiply the 2nd by 5, leave the first one alone
2e - 5d = 14
25e - 5d = 60
now subtract the 1st from the 2nd
23e = 46
e = 2
sub that back into the original 1st
5d = 2(2) - 14
5d = -10
d = -2
How to solve
5d=2e-14
5e=d+12. Using elimination method
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