How to get sum of 8 terms of a linear sequence whose first term is 6 and last 48

Answer 1

The sum of 8 terms of a linear sequence whose first term is 6 and last 48 can be calculated using the formula for the sum of an arithmetic sequence.

Sum = (n/2)(a1 + a2)

Where n is the number of terms, a1 is the first term, and a2 is the last term.

In this case, n = 8, a1 = 6, and a2 = 48.

Sum = (8/2)(6 + 48)

Sum = (8/2)(54)

Sum = 432

Answer 2

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