How to find the zeros of -16t^2 + 200 = 0?

Answer 1

- 16 t ^ 2 + 200 = 0 Subtract 200 to toth sides

- 16 t ^ 2 + 200 - 200 = 0 - 200

- 16 t ^ 2 = - 200 Divide both sides by - 16

- 16 t ^ 2 / - 16 = - 200 / - 16

t ^ 2 = - 200 / -16

t ^ 2 = 200 / 16

t ^ 2 = 4 * 50 / ( 4 * 4 )

t ^ 2 = 50 / 4

t ^ 2 = 2 * 25 / ( 2 * 2 )

t ^ 2 = 25 / 2

t = + OR - sqroot ( 25 / 2 )

t = + OR - sqroot ( 25 ) / sqroot ( 2 )

t = + OR - 5 / sqroot ( 2 )

t1 = 5 / sqroot ( 2 )

t2 = - 5 / sqroot ( 2 )