Asked by jamar
how to find the volume of oxygen at STP from the Deoomposition of 10.8 g of mercuric oxide?
Answers
Answered by
DrBob222
2HgO ==> 2Hg + O2
2. Convert 10.8 g HgO to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles HgO to moles O2.
4. Convert mols O2 to volume. L = 22.4 L/mol x moles
2. Convert 10.8 g HgO to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles HgO to moles O2.
4. Convert mols O2 to volume. L = 22.4 L/mol x moles
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