add the last two:
2yz-3zx+8xy=4
subtract the first
2yz-3zx+8xy=4
-2yz-zx+5xy=-2
or combining
-zx+13xy=2
a) x(13y-z)=2
add the first two equation
3yz-3xy=3
y(3z-3x)=3
b) y(z-x)=1
then, subtract 3x the second frm the third
-3YZ+3ZX-6XY=-3
YZ-2ZX+6XY=3
OR
-3yz+xz=0
c( z(x-3y)=0 which means that x is zero, or z-3y=0; z=3y
Now, having that, go to equation c)
if x-0, then z is xero, or y is zero, or both.
Go to the other equations a) and b), and explore solutions. Have a pad of paper handy.
How to find the values of x,y and z and to show the condition stated below?
2yz + zx − 5xy = 2
yz − zx + 2xy = 1
yz − 2zx + 6xy = 3
Show that xyz = ±6 and find all possible values of x, y and z.
1 answer
1 answer