How to find the solution set in a+bi form for this equation?

Question

6x^2+4x+1=0

PLEASE HELP!THANKS!!!!

Answer 1

Use the quadratic equation. In your case the constants are a=6, b=4 and c=1.

x = -b +/-sqrt(b^2-4ac)]/12

The b^2 - 4ac term is negative, and that will provide the imaginary term.

x = [-4 +/-sqrt(-8)]/12 = -1/3 +/- (sqrt2)/6 i