x = 2log4 y
log4 y = (x/2)
4^log4 y = 4^(x/2)
y = 4^.5x
How to find the inverse of y = log(4)x^2
4 answers
So I have to simplify and then get the exponential?
4^.5x = (4^.5)^x = 2^x
This is easy to see, since log_4(x^2) = 2log_4(x) = log_2(x)
This is easy to see, since log_4(x^2) = 2log_4(x) = log_2(x)
Thanks to both!