When you don't give a specific question it is tough to answer. This is a general question and has two or three answers depending upon what the aq solution is.
If it is a solution of an acid or base it is done one way. If it is a salt which has hydrolyzed it is done another way. Do you have a preference? I'm not too interested in doing both.
how to find ph of aqueous solution if your only given the concentration
3 answers
What is the pH of an aqueous solution that is 8.5*10^-2 M NaOCl?
The Na^+ is not hydrolyzed. The OCl^- is hydrolyzed.
........OCl^- + HOH ==> HOCl + OH^-
I.......0.085...........0........0
C.........-x............x.......x
E.......0.085-x........x.........x
Kb for OCl^- = (Kw/Ka for HOCl) = (HOCl)(OH^-)/(OCl^-)
Substitute from the ICE chart into the Kb for OCl^- expression and solve for x = (HOCl) = (OH^-).
Use OH^- to solve for pOH = -log(OH^-) then pH + pOH = pKw = 14.Solve for pH.
........OCl^- + HOH ==> HOCl + OH^-
I.......0.085...........0........0
C.........-x............x.......x
E.......0.085-x........x.........x
Kb for OCl^- = (Kw/Ka for HOCl) = (HOCl)(OH^-)/(OCl^-)
Substitute from the ICE chart into the Kb for OCl^- expression and solve for x = (HOCl) = (OH^-).
Use OH^- to solve for pOH = -log(OH^-) then pH + pOH = pKw = 14.Solve for pH.