better typing:
x = (a^2 + a - 2)/(a-1)
x = (a+2)(a-1)/(a-1)
= a+2
so if a = 888 888 888 888
x = 888 888 888 888 + 2
x = 888 888 888 890
How to do this sum
x=a2+a-2
______ if a= 888 888 888 888
a-1
2 answers
I don't understand please explain futher