How to do this sum

x=a2+a-2
______ if a= 888 888 888 888
a-1

2 answers

better typing:
x = (a^2 + a - 2)/(a-1)

x = (a+2)(a-1)/(a-1)
= a+2

so if a = 888 888 888 888
x = 888 888 888 888 + 2
x = 888 888 888 890
I don't understand please explain futher
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