how to differentiate 500x^2 [(280+x^2)^-1/2] +10x?

Answer 1

let y = (500x^2)(280 + x^2)^(-1/2) + 10x

dy/dx = 500x^2(-1/2)(280 + x^2)^(-3/2) (2x) + 1000x(280 + x^2)^(-1/2) + 10

this is your "first-line" derivative.
I don't know to what level of simplification you have to take it.

Answer 2

i got to that step and got stuck, but cant seem to simplify it correctly. Thanks for your feedback! Appreciate it :)

Answer 3

oh nvm, I got it. i didn't isolate the 10. Thanks!