Not quite.
6.01 kJ/mol x 3.50 mol = ??
Note that your arrangement gives kJ/mol; my arrangement the mol cancel to give kJ as the answer and that is the quantity of heat.
How to calculate the quantity of heat gained or lost in the following change:
3.50 mol of water freezes at 0 degrees C?
Would it be 6.01kJ/ 3.50 mol ?
3 answers
21kj lost
-21.0 KJ (21.0 KJ lost)