How mucn 0.6 M barium chloride solution would be needed to completely react with 150mL of a 1.4 M sodium solution

Question

bobpursley · Answer

Well, barium is ++ ion, and sodium is + ion, so it will thake half as much barium to react. moles barium= 1/2*.150L*1.4M or moles barium=.075*1.4 volume bariumchloride= .074*1.4/.6

DrBob222 · Answer

I am poking my head in where I've not been asked to poke but I assume you intended to write sodium sulfate and not just sodium. I don't know how you react BaCl2 with sodium ion. Do they do anything except look at each other?