Ro + Ro*0.0068/oC*(T2 -T1) = 1.15Ro.
Divide both sides by Ro:
0.0068/oC*(T2-20) = 1.15,
T2-20 = 169,
T2 = 189oC.
%Increase = ((T2-T1)/T1)*100%
%Increase = ((189-20)/20)100 = 845%.
how much would you have to raise the temperature of a copper wire(originally at 20degree celcius) to increase its resistance by 15%? express your answer in percentage.note a=0.0068per degree celcius
1 answer