How much work must be done to stop a 1150-kg car traveling at 145 km/h?

Answer 1

I will be happy to critique your thinking.

Answer 2

The car does the work equal to the initial kinetic energy. Unless it hits a spring, or it is a hybrid car, the work done is converted to heat.

Answer 3

convert 145 km/h into m/s
145 × 1000 ÷ 3600= 40.3
then use this equation:
W=Fd

Answer 4

or use
KE= 1/2 mv^2
depending on what is given

Answer 5

Vmch
Gjf