ml1 x M1 = mL1 x M2
mL1 x 3.25M = 400 mL x 0.250
Solve for mL1 volume, take that volume of the stock, transfer to a 400 mL volumetric flask and make to the mark with distilled water. Stopper. mix thoroughly, label. Done.
How much Tris-Acetate-EDTA (TAE) stock buffer (3.25 M) is required to make 400 ml of solution that has a concentrations of 250 mM? How much water?
1 answer
1 answer