mols CaCO3 = grams/molar mass
mols EDTA = mols CaCO3 (it's always 1:1)
Then M EDTA = mols EDTA/L EDTA
Solve for L EDTA and convert to mL if desired.
How much titrant will be required if your EDTA titrant is exactly 0.01 M and you weighed out exactly 0.4 g calcium carbonate?
1 answer