how much tension must a rope withstand if it is used to accelerate a 1200-kg car vertically upward at .80 m/s^2?

Answer 1

Force required to accelerate the car vertically = m * (v^2)

= 1200 * (0.8^2)

= 1200 * 0.64

This force will be equal to the tension on the rope.

Answer 2

these are the answer choices though


Problem 10
13000 N
12000 N
11000 N
10000 N

Answer 3

13000N
12000N
11000N
10000N

Answer 4

tension=mg+ma=m(9.8+.8)= to two decimal places.