if x ml of 100% alcohol are added, then you want
.15(400) + 1.00x = .32(400+x)
How much pure alcohol has to be added to 400ml of a solution containing 15% alcohol to change the concentration of alcohol in the mixture to 32%?
2 answers
Qus-a sum of 500 Rs is in the form of denominations of 5 and 10 if the total numder of notes is 90 find the number of notes of each type
solve- lets 5Rs notes =x
10 Rs notes =(90-x)
Atoq
5¡Áx+10¡Á(90-x)=500
5x+900_10x=500
-5x=500-900
-5x=-400
5x=400
X=400/5
x=80
Number of 5 Rs notes =80
Number of 10 Rs nots=(90-x)
=(90-80)=10 ANSWER
solve- lets 5Rs notes =x
10 Rs notes =(90-x)
Atoq
5¡Áx+10¡Á(90-x)=500
5x+900_10x=500
-5x=500-900
-5x=-400
5x=400
X=400/5
x=80
Number of 5 Rs notes =80
Number of 10 Rs nots=(90-x)
=(90-80)=10 ANSWER
1 answer