How much pure acid must be added to 6 milliliters of a 5% acid solution to produce a 40% acid solution? Please Show All Work!

Answer 1

c1 v1 + c2 v2 = c3 (v1+v2)

5 x 6 + 100(Pure acid) x v2 =
40(6+v2)

30 + 100v2 = 240 + 40v2

60v2 = 210

v2 = 21/6 = 7/2 =
3.5ml is the answer