To find the power produced by the flashlight, you can use the formula:
\[ \text{Power (P)} = \text{Voltage (V)} \times \text{Current (I)} \]
In this case, the voltage \( V \) is 12 volts and the current \( I \) is \( 6.5 \times 10^{-2} \) amps.
Now, let's calculate the power:
\[ P = 12 , \text{V} \times 6.5 \times 10^{-2} , \text{A} \]
\[ P = 12 \times 0.065 = 0.78 , \text{watts} \]
So, the power produced by the flashlight is:
A. 0.78 watts