N = 14 g/mol
O = 16 g/mol
2 Mols N2O5 = 56+160 = 216 grams
1 mol O2 = 32 grams
so 32 grams O2 for each 216 grams N2O5
so
(32/216)44.2
How much oxygen (in grams) will form from 44.2 mg of N2O5?
2N2O5(s) → 4NO2(g) + O2(g)
____× 10^-3(g) O2
1 answer