How much of solid potassium chromate whould you use to prepare 2.00 L of 0.400 M potassium chromate?
M x L = mols
g/molar mass = mols OR
M x L = g/molar mass
solve for g.
.400 mol/L x 2.00 = g/194
g = 155.2
Thanks!!
M x L = mols
g/molar mass = mols OR
M x L = g/molar mass
solve for g.
.400 mol/L x 2.00 = g/194
g = 155.2
Thanks!!