How much of a radioactive material with a half-life of 12,000 years is left after 36,000 years of decay?

Question

bobpursley · Answer

That is three half-lives? first half life 1/2 remaining second half life 1/4 remaining third half life 1/8 remaining amountrmaing=0riginalamount (1/2)^(t/th) where t is time, th is halflife time.

DrBob222 · Answer

I know I'm repeating myself, Angie; however, all of these problems can be worked with the formula I gave you and solved an example problem for you a couple of days ago. You need to learn to do these yourself instead of posting and obtaining answers from a third party. DrWLS, Bob Pursley, and I won't be with you when it comes test time.

bob · Answer

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